(8-3i)^2/(4-5i)

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Solution for (8-3i)^2/(4-5i) equation: 


D( i )

4-(5*i) = 0

4-(5*i) = 0

4-(5*i) = 0

4-5*i = 0

4-5*i = 0 // - 4

-5*i = -4 // : -5

i = -4/(-5)

i = 4/5

i in (-oo:4/5) U (4/5:+oo)

((8-(3*i))^2)/(4-(5*i)) = 0

((8-3*i)^2)/(4-5*i) = 0

8-3*i = 0 // - 8

-3*i = -8 // : -3

i = -8/(-3)

i = 8/3

i in { 8/3, 8/3 }

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